Fine-tuning CodeLlama-7B for Fortran Code Generation

You are given an integer n. A 0-indexed integer array nums of length n + 1 is generated in the following way:

nums[0] = 0
nums[1] = 1
nums[2 * i] = nums[i] when 2 <= 2 * i <= n
nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums.

Example 1:

Input: n = 7 Output: 3 Explanation: According to the given rules: nums[0] = 0 nums[1] = 1 nums[(1 * 2) = 2] = nums[1] = 1 nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2 nums[(2 * 2) = 4] = nums[2] = 1 nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3 nums[(3 * 2) = 6] = nums[3] = 2 nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3 Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is max(0,1,1,2,1,3,2,3) = 3.

Example 2:

Input: n = 2 Output: 1 Explanation: According to the given rules, nums = [0,1,1]. The maximum is max(0,1,1) = 1.

Example 3:

Input: n = 3 Output: 2 Explanation: According to the given rules, nums = [0,1,1,2]. The maximum is max(0,1,1,2) = 2.

Constraints:

0 <= n <= 100

Note: This problem is from LeetCode.

❌ Compiled

❌ Executed

❌ Correct

program main
    implicit none

    integer :: n, nums(n+1), max_val

    ! example 1
    n = 7
    call generate_array(n, nums)
    write(*,*) 'Example 1:'
    write(*,*) 'n = ', n
    write(*,*) 'nums = ', nums
    max_val = get_max(nums)
    write(*,*) 'Maximum value = ', max_val

    ! example 2
    n = 2
    call generate_array(n, nums)
    write(*,*) 'Example 2:'
    write(*,*) 'n = ', n
    write(*,*) 'nums = ', nums
    max_val = get_max(nums)
    write(*,*) 'Maximum value = ', max_val

    ! example 3
    n = 3
    call generate_array(n, nums)
    write(*,*) 'Example 3:'
    write(*,*) 'n = ', n
    write(*,*) 'nums = ', nums
    max_val = get_max(nums)
    write(*,*) 'Maximum value = ', max_val

contains

    subroutine generate_array(n, nums)
        implicit none
        integer, intent(in) :: n
        integer, intent(out) :: nums(n+1)

        nums(0) = 0
        nums(1) = 1
        do i = 2, n
            if (mod(i, 2) == 0) then
                nums(i) = nums(i/2)
            else
                nums(i) = nums(i/2) + nums((i+1)/2)
            end if
        end do
    end subroutine generate_array

    function get_max(nums) result(max_val)
        implicit none
        integer, intent(in) :: nums(:)
        integer :: max_val

        max_val = maxval(nums)
    end function get_max

end program main

stderr

temp.f95:4:28:

    4 |     integer :: n, nums(n+1), max_val
      |                            1
Error: Explicit shaped array with nonconstant bounds at (1)
temp.f95:12:11:

   12 |     max_val = get_max(nums)
      |           1
Error: Symbol ‘max_val’ at (1) has no IMPLICIT type
temp.f95:7:5:

    7 |     n = 7
      |     1
Error: Symbol ‘n’ at (1) has no IMPLICIT type
temp.f95:8:31:

    8 |     call generate_array(n, nums)
      |                               1
Error: Symbol ‘nums’ at (1) has no IMPLICIT type
temp.f95:42:12:

   42 |         do i = 2, n
      |            1
Error: Symbol ‘i’ at (1) has no IMPLICIT type
temp.f95:40:13:

   40 |         nums(0) = 0
      |             1
Warning: Array reference at (1) is out of bounds (0 < 1) in dimension 1

✅ Compiled

✅ Executed

⚠️ Correct

program max_array
      implicit none

      integer, parameter :: n = 7
      integer :: nums(n + 1)
      integer :: i

      ! Initialize the array
      nums(0) = 0
      nums(1) = 1
      do i = 2, n, 2
        nums(i) = nums(i / 2)
      end do
      do i = 3, n, 2
        nums(i) = nums(i / 2) + nums(i / 2 + 1)
      end do

      ! Print the maximum
      print *, maxval(nums)

      end program max_array

stdout

🌐 Data from online sources

def findKthPositive(arr, k):
    i, num = 0, 1
    while k > 0:
        if i < len(arr) and arr[i] == num:
            i += 1
        else:
            k -= 1
        num += 1
    return num - 1

Initialize two pointers i and num. i is used to iterate through the input array arr, and num is used to check if the integer is in the array.
Use a while loop that runs until k becomes 0. Inside the loop, we do the following:
Check if the current value of num is in the array (i.e., if arr[i] == num). If it is, increment i. This means the current value of num is not a missing number.
If the current value of num is not in the array, decrement k. This means we found one missing number.
Increment num.
When the loop ends, k becomes 0, meaning we found the kth missing number. The value of num - 1 is the kth missing positive integer. Return this value.

🌐 Data from online sources

int findKthPositive(vector<int>& arr, int k) {
    int i = 0, num = 1;
    while (k > 0) {
        if (i < arr.size() && arr[i] == num) {
            i++;
        } else {
            k--;
        }
        num++;
    }
    return num - 1;
}

Initialize two pointers i and num. i is used to iterate through the input array arr, and num is used to check if the integer is in the array.
Use a while loop that runs until k becomes 0. Inside the loop, we do the following:
Check if the current value of num is in the array (i.e., if arr[i] == num). If it is, increment i. This means the current value of num is not a missing number.
If the current value of num is not in the array, decrement k. This means we found one missing number.
Increment num.
When the loop ends, k becomes 0, meaning we found the kth missing number. The value of num - 1 is the kth missing positive integer. Return this value.

Get Maximum in Generated Array