import heapq

def busiest_servers(k, arrival, load):
    server_requests = [0] * k
    pq = []
    available_servers = list(range(k))

    for i in range(len(arrival)):
        while pq and pq[0][0] <= arrival[i]:
            _, server_id = heapq.heappop(pq)
            available_servers.append(server_id)

        if available_servers:
            server_id = available_servers.pop(0)
            server_requests[server_id] += 1
            heapq.heappush(pq, (arrival[i] + load[i], server_id))

    max_requests = max(server_requests)
    return [i for i in range(k) if server_requests[i] == max_requests]

1. Initialize an array named `serverRequests` to store the number of requests handled by each server. This array is the same length as the number of servers and filled with 0s initially. Initialize a priority queue `pq` to store the servers that are currently handling a request, in ascending order of when they will finish processing the request. Initialize a queue `availableServers` and fill it with server IDs from 0 to k-1.

1. Iterate over the arrival array. For each request, dequeue any servers that have finished processing their tasks, and enqueue them into availableServers.
2. If there are servers available in availableServers, then assign the current request to the first available server. Increment the corresponding count in serverRequests, and enqueue the server into pq with the finish time (arrival[i] + load[i]) as the priority.
3. Iterate through serverRequests to find the maximum count (i.e. the highest number of requests handled).
4. Finally, create a result list (or array) containing the IDs of servers with counts equal to the maximum count.

#include <vector>
#include <queue>

std::vector<int> busiestServers(int k, std::vector<int>& arrival, std::vector<int>& load) {
    std::vector<int> serverRequests(k, 0);
    std::priority_queue<std::pair<int, int>, std::vector<std::pair<int, int>>, std::greater<std::pair<int, int>>> pq;
    std::queue<int> availableServers;

    for (int i = 0; i < k; ++i) {
        availableServers.push(i);
    }

    for (int i = 0; i < arrival.size(); ++i) {
        while (!pq.empty() && pq.top().first <= arrival[i]) {
            availableServers.push(pq.top().second);
            pq.pop();
        }

        if (!availableServers.empty()) {
            int serverId = availableServers.front();
            availableServers.pop();
            serverRequests[serverId]++;
            pq.push({arrival[i] + load[i], serverId});
        }
    }

    int maxRequests = 0;
    for (int requests : serverRequests) {
        maxRequests = std::max(maxRequests, requests);
    }

    std::vector<int> result;
    for (int i = 0; i < k; ++i) {
        if (serverRequests[i] == maxRequests) {
            result.push_back(i);
        }
    }

    return result;
}

1. Initialize an array named `serverRequests` to store the number of requests handled by each server. This array is the same length as the number of servers and filled with 0s initially. Initialize a priority queue `pq` to store the servers that are currently handling a request, in ascending order of when they will finish processing the request. Initialize a queue `availableServers` and fill it with server IDs from 0 to k-1.

1. Iterate over the arrival array. For each request, dequeue any servers that have finished processing their tasks, and enqueue them into availableServers.
2. If there are servers available in availableServers, then assign the current request to the first available server. Increment the corresponding count in serverRequests, and enqueue the server into pq with the finish time (arrival[i] + load[i]) as the priority.
3. Iterate through serverRequests to find the maximum count (i.e. the highest number of requests handled).
4. Finally, create a result list (or array) containing the IDs of servers with counts equal to the maximum count.