Fine-tuning CodeLlama-7B for Fortran Code Generation

You are given two 0-indexed strings s and target. You can take some letters from s and rearrange them to form new strings.

Return the maximum number of copies of target that can be formed by taking letters from s and rearranging them.

Example 1:

Input: s = "ilovecodingonleetcode ", target = "code " Output: 2 Explanation: For the first copy of "code ", take the letters at indices 4, 5, 6, and 7. For the second copy of "code ", take the letters at indices 17, 18, 19, and 20. The strings that are formed are "ecod " and "code " which can both be rearranged into "code ". We can make at most two copies of "code ", so we return 2.

Example 2:

Input: s = "abcba ", target = "abc " Output: 1 Explanation: We can make one copy of "abc " by taking the letters at indices 0, 1, and 2. We can make at most one copy of "abc ", so we return 1. Note that while there is an extra 'a' and 'b' at indices 3 and 4, we cannot reuse the letter 'c' at index 2, so we cannot make a second copy of "abc ".

Example 3:

Input: s = "abbaccaddaeea ", target = "aaaaa " Output: 1 Explanation: We can make one copy of "aaaaa " by taking the letters at indices 0, 3, 6, 9, and 12. We can make at most one copy of "aaaaa ", so we return 1.

Constraints:

1 <= s.length <= 100
1 <= target.length <= 10
s and target consist of lowercase English letters.

Note: This problem is from LeetCode.

✅ Compiled

✅ Executed

❌ Correct

program main
    implicit none

    character(len=*), parameter :: s = "ilovecodingonleetcode "
    character(len=*), parameter :: target = "code "
    integer :: n

    n = maxCopies(s, target)
    write (*,*) n

contains

    function maxCopies(s, target) result(n)
        implicit none
        character(len=*), intent(in) :: s
        character(len=*), intent(in) :: target
        integer :: n
        integer :: i, j, k, l

        n = 0
        do i = 1, len(s)-len(target)+1
            do j = i+len(target)-1, len(s)
                if (s(i:j) == target) then
                    n = max(n, j-i+1)
                end if
            end do
        end do
    end function maxCopies
end program main

stdout

❌ Compiled

❌ Executed

❌ Correct

program maxCopies
      implicit none

      integer :: i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z
      integer :: max_copies
      character(len=100) :: s
      character(len=10) :: target

      read(*,*) s
      read(*,*) target

      max_copies = 0
      do i = 1, len(s) - len(target) + 1
          do j = i + 1, len(s) - len(target) + 1
              if (s(i:j) == target) then
                  max_copies = max_copies + 1
              end if
          end do
      end do

      write(*,*) max_copies

      end program maxCopies

stderr

temp.f95:6:29:

    6 |       character(len=100) :: s
      |                             1
Error: Symbol ‘s’ at (1) already has basic type of INTEGER
temp.f95:15:20:

   15 |               if (s(i:j) == target) then
      |                    1
Error: Syntax error in IF-expression at (1)
temp.f95:17:17:

   17 |               end if
      |                 1
Error: Expecting END DO statement at (1)
temp.f95:14:28:

   14 |           do j = i + 1, len(s) - len(target) + 1
      |                            1
Error: ‘string’ argument of ‘len’ intrinsic at (1) must be CHARACTER
temp.f95:13:20:

   13 |       do i = 1, len(s) - len(target) + 1
      |                    1
Error: ‘string’ argument of ‘len’ intrinsic at (1) must be CHARACTER

🌐 Data from online sources

def maxNumberOfCopies(s, target):
    s_counts = [0] * 26
    target_counts = [0] * 26

    for c in s:
        s_counts[ord(c) - ord('a')] += 1

    for c in target:
        target_counts[ord(c) - ord('a')] += 1

    max_copies = float('inf')
    for i in range(26):
        if target_counts[i] > 0:
            max_copies = min(max_copies, s_counts[i] // target_counts[i])
    return max_copies

1. Create two arrays `s_counts` and `target_counts` of length 26 to count the occurrences of each alphabet in both strings s and target.

Iterate through the input strings s and target, and calculate the frequency of each character in both strings s and target using their ASCII values.
Initialize a variable max_copies to store the maximum number of copies that can be formed.
Iterate through the target_counts from 0 to 25 (inclusive) and check if the count of each character is greater than 0. If yes, update max_copies with the minimum value between the current max_copies value and the integer division of s_counts and target_counts at that index.
Return the max_copies as the result.

🌐 Data from online sources

#include <string>
#include <vector>

int maxNumberOfCopies(std::string s, std::string target) {
    std::vector<int> s_counts(26, 0);
    std::vector<int> target_counts(26, 0);

    for (char c : s)
        s_counts[c - 'a']++;

    for (char c : target)
        target_counts[c - 'a']++;

    int max_copies = INT32_MAX;
    for (int i = 0; i < 26; i++) {
        if (target_counts[i] > 0)
            max_copies = std::min(max_copies, s_counts[i] / target_counts[i]);
    }
    return max_copies;
}

1. Create two arrays `s_counts` and `target_counts` of length 26 to count the occurrences of each alphabet in both strings s and target.

Iterate through the input strings s and target, and calculate the frequency of each character in both strings s and target using their ASCII values.
Initialize a variable max_copies to store the maximum number of copies that can be formed.
Iterate through the target_counts from 0 to 25 (inclusive) and check if the count of each character is greater than 0. If yes, update max_copies with the minimum value between the current max_copies value and the integer division of s_counts and target_counts at that index.
Return the max_copies as the result.

Rearrange Characters to Make Target String